Monday, April 16, 2012

If it takes three "breaths" to blow up a balloon to 1.2 , and each breath supplies the balloon with 0.060 moles of exhaled air, how many moles of air are in a 3.0 balloon?


If it takes three "breaths" to blow up a balloon to 1.2 \rm L, and each breath supplies the balloon with 0.060 moles of exhaled air, how many moles of air are in a 3.0 \rm L balloon?
Express your answer to two decimal places and include the appropriate units.
0.45  mol
Correct
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3 comments:

  1. AnonymousMarch 10, 2013 at 4:45 PM

    how did you get .45 moles

    ReplyDelete
  2. AnonymousMarch 13, 2013 at 12:01 PM

    Notice that the question mentions that it takes Three breathes to fill up the balloon to 1.2 L. The following information that they give us is that each breath supplies .060 moles to fill up the balloon to 1.2 L.

    Your proportion is
    v1/v2=n1/n2

    So you take
    (n1).060 * 3= .18 (n1)

    .18* 3.0(v2)=.54

    .54/1.2(v1)=.45(n2)

    ReplyDelete
  3. UnknownMarch 26, 2016 at 5:49 AM

    N=0.15*3 breaths

    ReplyDelete

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