College Submissions: Elemental analysis of the unknown gas from Part A revealed that it is 30.45 and 69.55 . What is the molecular formula for this gas?

Monday, April 16, 2012

Elemental analysis of the unknown gas from Part A revealed that it is 30.45 and 69.55 . What is the molecular formula for this gas?

Elemental analysis of the unknown gas from Part A revealed that it is 30.45 $\%$ $\rm N$ and 69.55 $\%$ $\rm O$ . What is the molecular formula for this gas?

Express your answer as a chemical formula.

$\rm{N_{2}O_{4}}$

Correct

1 comments:

UnknownMarch 24, 2022 at 9:21 PM
N2O4 you multiply the percent's by your mass percent, divide by molar mass and then there's your answer no need to simplify.
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