Wednesday, July 4, 2012

0.5g of zinc powder was found to reduce an acidified solution of 25.50 cm^3 of 0.200 mol/dm^3 AO2^+ . What Is the final oxidation number of metal A . Options : A) 0. B) +1 C) +2. D) +3

0.5 g / 65.409 g/mol = 0.0076442 mol of Zn

Zn ---> Zn2+ + 2e-

0.0076442 mol times2 = 0.0152884 mol of electrons produced

MV = moles

(0.200 mol/L) (0.02550 L ) = 0.0051 mol of AO2^+

0.0152884 mol / 0.0051 mol = 2.998 = 3

In AO2^+, the oxidation number of A is +5. It was reduced by 3 oxidation numbers to +2.

Answer choice C
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2 comments:

  1. AnonymousJuly 5, 2012 at 6:12 PM

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