A 0.274 M solution of sulfuric acid (H2SO4) is to be reacted with a 0.266 M solution of sodium hydroxide to make sodium sulfate and water. How many L of the H2SO4 solution will react with 0.867 L of the NaOH solution?

NaOH ---> (0.266 mol/L) (0.867 L) = 0.230622 mol

H2SO4 + 2NaOH ---> Na2SO4 + 2H2O

For every two NaOH used up, one H2SO4 reacts.

H2SO4 ---> 0.230622 mol / 2 = 0.115311 mol

(0.274 mol/L) (x) = 0.115311 mol

x = 0.421 L (to three sig figs)